Varying variables - Dev Hardware

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May 20th, 2011, 07:50 PM

BobaFett2040

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Varying variables

I'm trying to make an inventory program for my TI-83 Calculator. What I need it to do is to prompt a user for the number of items, and create prompts for each one.

Example:

Number of Items:
User inputs, say 4.
The program then asks for the value of 4 items, as the program only created 4 variables.

Is that possible outside of using assembly?

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May 21st, 2011, 10:31 PM

MufinMcFlufin

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Quote:

Originally Posted by BobaFett2040

You'll want to use a List, commonly known as an Array in other programming languages, except with one dimension. A list is a collection of numbers, with one dimension, much like what one would normally think of when you say list.

Because a List is a one dimensional object or variable, to store or call from a list, you need to specify to or from which element of the list. If you don't specify, then it will assume you're trying to replace the entire list. The calculator has a few built in lists, of which being L1 (List 1) through L6 (List 6). You can find these lists on the number pad of your calculator, after pressing [2nd].

Another thing to specify before going on, a list require dimensions. It cannot hold an infinite number of variables, and is limited either by memory, or specified dimensions.

In TI BASIC, a list by default will not exist. Even if it does exist, it by default will have dimensions of 0, meaning it has no slots for variable placement. Before you can use a list, you must define it, and then set it's dimensions. Most often you can do both of these in one step, so we will.

Here's a small code, where the program set's L1's dimensions to 5, meaning there are 5 elements where you can store variables. Then after setting the dimensions, it will store the value 2 into the first element of L1, 3 into the second, etc.

Code:

5->dim(L1
2->L1(1
3->L1(2
10->L1(3
6->L1(4
0->L1(5

You can also use variables to store dimensions, values, and values into variable elements. Here's an example:

Code:

Input "dim(",A
A->dim(L1
Input "L1(1)=",B
B->L1(1
Input "1=L1(C)",C
1->L1(C

Now given you don't input invalid dimensions (negative, imaginary, or non-integer number, or if it exceeds the set dimensions, applies to C, and B if A is 0) then it will work properly.

You can use this for the code you were asking for.

Now, I can't cover all of the information, so if you want to learn more about lists, then here's a link to an article with more information.

__________________
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May 23rd, 2011, 07:58 AM

BobaFett2040

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Thanks. I'll check it out first chance I get.

Quote:

Originally Posted by MufinMcFlufin

Code:

5->dim(L1
2->L1(1
3->L1(2
10->L1(3
6->L1(4
0->L1(5

You can also use variables to store dimensions, values, and values into variable elements. Here's an example:

Code:

Input "dim(",A
A->dim(L1
Input "L1(1)=",B
B->L1(1
Input "1=L1(C)",C
1->L1(C

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June 1st, 2011, 08:35 AM

PAR

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BobaFett2040, I guess this code will be usefull.

Code:

Input "ITEMS",A
A->dim(L1
Ipart(Abs(A))->A
For (X,1,A)
Output (1,1,”ITEM-NUMBER=)
Output (1,13,A)
Input "DATA=",B
B->L1(X
Output (5,6,”[OK]
Pause
CrlDraw
End