How to use Output to display value in fraction

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February 16th, 2008, 10:52 AM

SilverDragon

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How to use Output to display value in fraction

I want to display some quote/string and some values(fraction) in one line, how can i do

something like this
"+"{a quote} {value of A^C>Frac} "X^" {value of 2C}

currently my problems is that when i use "output", i can put several elements in a line, but then ">Frac" cant be used, if i use "Disp"(which enable me to use >Frac) then i cant place all the elements in a same line.

can anyone help me, i have been using my gc for one week only.

thx

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April 2nd, 2008, 12:33 PM

MrLarkins

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Quote:

Originally Posted by SilverDragon

hmm, watch the process, this may help:

Code:

.75->A
.75*100->A
gcd(A,100)->B
A/B->C
100/B->D
Output(1,1,C)
Output(1,3,"/")
Output(1,5,D)

i left space so that it displays "3 / 4" instead of "3/4"...so that double digits are allowed. if you think you need triple digist you can give more space. if you want it to float, then you need more code.

but do you understand the math of finding the numerator and denominator?

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April 2nd, 2008, 12:57 PM

MrLarkins

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fixed it up a bit and made it fancy...now it floats

Code:

Prompt A     //decimal to convert to fraction
A*10000->A
gcd(A,10000)->B
A/B->C
10000/B->D
If C/10<1
Then
1->Z
Goto 99
Else
If C/100<1
Then
2->Z
Goto 99
Else
If C/1000<1
Then
3->Z
Goto 99
Else
4->Z      //Should be enough space
End
Lbl 99
ClrHome
Output(1,1,C)
Output(1,1+Z,"/")
Output(1,2+Z,D)

and that will handle a 4 digit numerator with any size denominator.

enjoy!

Last edited by MrLarkins : April 14th, 2008 at 01:39 PM.

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April 14th, 2008, 12:34 PM

zilchonum

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Improvement

I like that solution, but it would be easier to do "int(log(x))+1" instead of checking to find the number of digits.

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April 14th, 2008, 12:43 PM

Jagraffamel

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The only person who knows anything on here is zilchonum, I wrote one that makes ANY decimal (so long as it isn't irrational...) that only has about 16 lines...only takes up 160 bytes...so...

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April 14th, 2008, 01:38 PM

MrLarkins

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Quote:

Originally Posted by zilchonum

I like that solution, but it would be easier to do "int(log(x))+1" instead of checking to find the number of digits.

very nice digit finder...eloquent, i've never seen that before.

but i incorporated it into the program

Code:

Prompt A     //decimal to convert to fraction
A*10000000->A
gcd(A,10000000)->B
A/B->C
10000000/B->D
int(log(C))+1->Z
Lbl 99
ClrHome
Output(1,1,C)
Output(1,1+Z,"/")
Output(1,2+Z,D)

that cut the code quite a bit. thanks.

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April 14th, 2008, 04:13 PM

Jagraffamel

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What if you have the number .001020102010201020102010201020...?

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April 15th, 2008, 07:51 AM

MrLarkins

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how likely is that, i mean get serious...even the most sophisticated calculators have a digit limit of 8 or 9

even the TI84's built in >FRAC feature won't convert YOUR decimal to a fraction.

be helpful instead of a nuisance

Last edited by MrLarkins : April 15th, 2008 at 07:56 AM.

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April 15th, 2008, 09:22 PM

Jagraffamel

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No, I mean that as a repeating decimal...

Or how about if it is .11111111111111111111111111111 or the fraction 1/9, it isn't going to be able to calculate that very well.

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April 16th, 2008, 08:15 AM

zilchonum

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More of a solution

My friend actually made a program like this. I helped him... what we did was multiply the number by 10, in a loop, then we checked if the fractional part cancelled out, like this:

.010101->N
N->T
for(A,1,10)
10T->T
if fPart(T-N)<(10^-A)
Then
A->R:10->A
End
End

Basically, you can take R (the number of repeated digits) and do something with that to format the fraction. Jaggraffamel should know more about that...

I'm not sure if that's the actual code (or if it works as is) but that's the general idea... hope it's useful.

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April 16th, 2008, 11:54 AM

MrLarkins

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Quote:

Originally Posted by zilchonum

My friend actually made a program like this. I helped him... what we did was multiply the number by 10, in a loop, then we checked if the fractional part cancelled out, like this:

.010101->N
N->T
for(A,1,10)
10T->T
if fPart(T-N)<(10^-A)
Then
A->R:10->A
End
End

Basically, you can take R (the number of repeated digits) and do something with that to format the fraction. Jaggraffamel should know more about that...

I'm not sure if that's the actual code (or if it works as is) but that's the general idea... hope it's useful.

that's very nice, i'd would have never thought of that....but you got a parathesis in the wrong spot.

Code:

Prompt->N
N->T
for(A,1,10)
10T->T
if fPart(T)-N<(10^-A)
Then
A->R:10->A
End
End

but how to integrate that into a program that does both terminating and repeating decimels...and then also decimals that have a non-repeating part before the repeating part, like .00102010201020102...

hmmm, more thinking.

Last edited by MrLarkins : April 16th, 2008 at 11:56 AM.

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April 16th, 2008, 03:23 PM

Jagraffamel

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It's already done. Would you like me to just show you, or allow you think for a while. It's a very simple program. I took a slightly different approach. The method you are using now definitely won't work thought. You will have to use -log( function to make it work out properly.

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April 16th, 2008, 03:30 PM

MrLarkins

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let me think for a day, then post it.

thanks

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April 17th, 2008, 12:29 PM

zilchonum

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...

Quote:

Originally Posted by Jagraffamel

Well, theoretically, it would. You see, the only decimals that repeat have denominators that end in 1, 3, 7, and 9. Google 'Vedic Mathematics' and look for "by one more than the one before" to see what I mean. You could probably reverse the division alg (from Vedic Math) to come out with a workable fraction (with a denominator that ends in 9), which could then be reduced through factoring. All the other denominators don't repeat, however, so there is no problem, see?

If you don't quite understand, just say so. I'll try to show the act